# This program computes the fibonacci numbers using recursion (O(2^n))
# It is very slow
func fib(x: number) number {
	if x <= 1 {
		return x
	}
	return fib(x - 1) + fib(x - 2)
}

n := 0
while n < 100 {
	write(str(fib(n)))
	n = n + 1
}